In the given figure, P &Q lie on xz plane and S &T lie on yz plane. The direction of magnetic moment of the loop carrying current I is given by

Question

In the given figure, P &Q lie on xz plane and S &T lie on yz plane. The direction of magnetic moment of the loop carrying current I is given by <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-isqsgyo2s40pwpbi.jpg" /> (A) ( hati + hatj/√2) (B) -(( hati + hatj/√2)) (C) ( hati + hatk/√2) (D) ( hati - hatk/√2)

Tardigrade Admin · Accepted Answer

For P Q R U vecμ=-I a2 hat jmath For RUTS vecμ=-I a2 hat imath μ text net =-( hati+ hatj/√2)

Q. In the given figure, $P & Q$ lie on $x z$ plane and $S & T$ lie on $yz$ plane. The direction of magnetic moment of the loop carrying current $I$ is given by

$\frac{i ^ + j ^}{2}$

$- (\frac{i ^ + j ^}{2})$

$\frac{i ^ + k ^}{2}$

$\frac{i ^ - k ^}{2}$

For $PQR U$
$μ = - I a^{2} \overset{}{^}$
For RUTS
$μ = - I a^{2} \overset{}{^}$
$μ_{net} = - \frac{i ^ + j ^}{2}$

Q. In the given figure, P&Q lie on xz plane and S&T lie on yz plane. The direction of magnetic moment of the loop carrying current I is given by

2​i^+j^​​

−(2​i^+j^​​)

2​i^+k^​

2​i^−k^​