In the given figure a capacitor of plate area A is charged up to charge q . The mass of each plate is m2 . The lower plate is rigidly fixed. Find the value of m1 so that the system remains in equilibrium -

Question

In the given figure a capacitor of plate area A is charged up to charge q . The mass of each plate is m2 . The lower plate is rigidly fixed. Find the value of m1 so that the system remains in equilibrium - <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-g5arllbcrqhd.png" /> (A) m2+(q2/ϵ 0 A g) (B) m2 (C) (q2/2 ϵ 0 A g)+m2 (D) 2m2

Tardigrade Admin · Accepted Answer

Now T=m2g+Fe l e c ldots (1) T=m1g .......(2) <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-g5arllbcwshk.png" /> m1g=m2g+(q2/2 A ϵ 0) m1=m2+(q2/2 A ϵ 0 g)

Q. In the given figure a capacitor of plate area $A$ is charged up to charge $q$ . The mass of each plate is $m_{2}$ . The lower plate is rigidly fixed. Find the value of $m_{1}$ so that the system remains in equilibrium -

$m_{2} + \frac{q ^{2}}{ϵ _{0} A g}$

$m_{2}$

$\frac{q ^{2}}{2 ϵ _{0} A g} + m_{2}$

$2 m_{2}$

Now $T = m_{2} g + F_{e l ec} \dots (1)$
$T = m_{1} g ....... (2)$

$m_{1} g = m_{2} g + \frac{q ^{2}}{2 A ϵ _{0}}$
$m_{1} = m_{2} + \frac{q ^{2}}{2 A ϵ _{0} g}$

Q. In the given figure a capacitor of plate area A is charged up to charge q . The mass of each plate is m2​ . The lower plate is rigidly fixed. Find the value of m1​ so that the system remains in equilibrium -

m2​+ϵ0​Agq2​

m2​

2ϵ0​Agq2​+m2​

2m2​