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Tardigrade
Question
Physics
In the given circuit potential of point A is 3000 V and of C is 1000 V. Then potential of point B is
Q. In the given circuit potential of point A is
3000
V
and of
C
is
1000
V
. Then potential of point B is
1917
183
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A
2000 V
B
1600 V
C
1500 V
D
1400 V
Solution:
Effective capacitance of circuit -
4
μ
F
Charge stored in system
q
=
4
×
2000
=
8000
μ
C
V
A
−
C
q
=
V
B
3000
−
5
8000
=
V
B
V
B
=
1400
V