Question

In the given circuit find reading of ammeter (in A) when capacitor has attained steady state. (Approximate the answer to the nearest integer)

Answer 1

Answer: 4

When the capacitor has attained steady-state, it will behave as an open circuit.
So, the circuit will be as shown

Simplifying the circuit from the combination of $2\Omega$ , $1\Omega$ and $6\Omega$ .
$R=\frac{\left(2+1\right)\times 6}{2+1+6}=2\Omega$

This circuit is a balanced wheatstone bridge.
So, the $5.2\Omega$ resistor will be as in an open circuit.
The equivalent resistance, $R_{eq}=\frac{\left(2+1\right)\times \left(8+4\right)}{\left(2+1\right)+\left(8+4\right)}=2.4\Omega$
The reading of the ammeter $I=\frac{10}{2.4}\approx 4.16A$