In the given arrangement, n number of equal masses are connected by strings of negligible masses. The tension in the string connected to n th mass is

Question

In the given arrangement, n number of equal masses are connected by strings of negligible masses. The tension in the string connected to n th mass is (A) (m M g/n m+M) (B) (m M g/n m M) (C) m g (D) m n g

Tardigrade Admin · Accepted Answer

The system may be represented as follow

From the force diagram, M g-T=M a ...(i) andT=n m a ...(ii) From Eqs. (i) and (ii), we get a=(M g/n m+M) The force diagram of n th block is shown in figure.

From the figure, Tn=m a =(m M g/n m+M)

Q. In the given arrangement, $n$ number of equal masses are connected by strings of negligible masses. The tension in the string connected to $n$ th mass is

$\frac{m M g}{nm + M}$

$\frac{m M g}{nm M}$

$m g$

$mn g$

The system may be represented as follow

From the force diagram,
$M g - T = M a ... (i)$
and $T = nma ... (ii)$
From Eqs. (i) and (ii), we get
$a = \frac{M g}{nm + M}$
The force diagram of $n$ th block is shown in figure.

From the figure,
$T_{n} = ma = \frac{m M g}{nm + M}$

Q. In the given arrangement, n number of equal masses are connected by strings of negligible masses. The tension in the string connected to n th mass is

nm+MmMg​

nmMmMg​

mg

mng