Question

In the following unbalanced equation, the molar mass of the product ${}^{\prime }{X}^{\prime }$ is ------ $g/mol.$
$($ At Wt. $Ca=40u,B=10.8u,O=16u,S=32u,H=1u)$
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Round off answer to the nearest integer value.

Answer 1

Answer: 62

The reaction is $\underset{\text{Colemanite}}{{\left(\text{Ca}\right)}_{\text{2}}{\left(\text{B}\right)}_{\text{6}}{\left(\text{O}\right)}_{\text{11}}}{\left(\text{+4SO}\right)}_{\text{2}}{\left(\text{+11H}\right)}_{\text{2}}\text{O}\to 2\text{Ca}({\left(\text{HSO}\right)}_3{)}_2+\underset{(Mol.mass=61.8gmo{l}^{-1})}{\underset{Orthoboricacid}{6{\left(\text{H}\right)}_3{\left(\text{BO}\right)}_3}}$