In the following common emitter circuit, if β =100 , VCE=7V , RC=2kΩ and VBE is negligible, then IB is

Question

In the following common emitter circuit, if β =100 , VCE=7V , RC=2kΩ and VBE is negligible, then IB is <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-qixyoaasjceld4rh.jpg" /> (A) 0.01 textmA (B) 0.04 textmA (C) 0.02 textmA (D) 0.03 textmA

Tardigrade Admin · Accepted Answer

V=VC E+ICRC ⇒ 15=7+IC× 2× 103⇒ IC=4mA ∵ β =(IC/IB)⇒ IB=(4/100)=0.04 mA

Q. In the following common emitter circuit, if $β = 100$ , $V_{CE} = 7 V$ , $R_{C} = 2 k Ω$ and $V_{BE}$ is negligible, then $I_{B}$ is

$0.01 mA$

$0.04 mA$

$0.02 mA$

$0.03 mA$

$V = V_{CE} + I_{C} R_{C}$
$\Rightarrow 15 = 7 + I_{C} \times 2 \times 1 0^{3} \Rightarrow I_{C} = 4 m A$
$∵ β = \frac{I _{C}}{I _{B}} \Rightarrow I_{B} = \frac{4}{100} = 0.04 m A$

Q. In the following common emitter circuit, if β=100 , VCE​=7V , RC​=2kΩ and VBE​ is negligible, then IB​ is

0.01mA

0.04mA

0.02mA

0.03mA