In the figure, two straight conducting rails form a right angle. A conducting bar in contact with the rails starts at the vertex at time t=0 and moves with a constant velocity of v along them. A magnetic field B is directed out of the page. The current in the loop is (.λ = resistance per unit length of the rails and bar).

Question

In the figure, two straight conducting rails form a right angle. A conducting bar in contact with the rails starts at the vertex at time t=0 and moves with a constant velocity of v along them. A magnetic field B is directed out of the page. The current in the loop is (.λ = resistance per unit length of the rails and bar). <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-vs2ifxruiabmqihp.jpg" /> (A) (2 B v/λ ) (B) (B v/λ (1 + √2)) (C) (√2 B v/λ ) (D) (2 B v/λ (1 + √2))

Tardigrade Admin · Accepted Answer

EMF=(d/d t)(B v t × v t)=2Bv2t and resistance =λ (2 v t + 2 √2 v t)

$\frac{2 B v}{λ}$

$\frac{B v}{λ ( 1 + 2 )}$

$\frac{2 B v}{λ}$

$\frac{2 B v}{λ ( 1 + 2 )}$

$EMF = \frac{d}{d t} (B v t \times v t) = 2 B v^{2} t$
and resistance $= λ (2 v t + 22 v t)$

λ2Bv​

λ(1+2​)Bv​

λ2​Bv​

λ(1+2​)2Bv​

EMF=dtd​(Bvt×vt)=2Bv2t and resistance =λ(2vt+22​vt)

$\frac{2 B v}{λ}$

$\frac{B v}{λ ( 1 + 2 )}$

$\frac{2 B v}{λ}$

$\frac{2 B v}{λ ( 1 + 2 )}$

$EMF = \frac{d}{d t} (B v t \times v t) = 2 B v^{2} t$
and resistance $= λ (2 v t + 22 v t)$