Q.
In the figure three identical springs are shown. From spring A, a mass of 4kg is hung and spring shows elongation of 1cm. But when a weight of 6kg is hung on B, the hook descends through
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Mechanical Properties of Solids
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Solution:
As, x=kr
If spring constant is k for the first case, it is 2k for second case.
For first case, 1=k4 ... (i)
For second case, x′=k/26=k12 ... (ii)
Dividing Eq. (ii) by Eq. (i), we get x′=4/k12/k=3cm