In the figure shown, m1=10 kg, m2=6 kg, m4=4 kg . If T3=40 N, T2=?

Question

In the figure shown, m1=10 kg, m2=6 kg, m4=4 kg . If T3=40 N, T2=? (A) 13 N (B) 32 N (C) 25 N (D) 35 N

Tardigrade Admin · Accepted Answer

Let α be the acceleration of each block. Then, T3=(m1+m2+m3) a ldots (i) and T2=(m1+m2) a ldots (ii) From Eqs. (i) and (ii), we get T2=((m1+m2/m1+m2 ± m3)) × T3 =((10+6/10+6+4)) × 40=32 N

Q. In the figure shown, $m_{1} = 10 k g, m_{2} = 6 k g, m_{4} = 4 k g .$ If $T_{3} = 40 N, T_{2} =$ ?

13 N

32 N

25 N

35 N

Let $α$ be the acceleration of each block. Then,
$T_{3} = (m_{1} + m_{2} + m_{3}) a \dots$ (i)
and $T_{2} = (m_{1} + m_{2}) a \dots$ (ii)
From Eqs. (i) and (ii), we get
$T_{2} = (\frac{m _{1} + m _{2}}{m _{1} + m _{2} \pm m _{3}}) \times T_{3}$
$= (\frac{10 + 6}{10 + 6 + 4}) \times 40 = 32 N$

Q. In the figure shown, m1​=10 kg,m2​=6 kg,m4​=4 kg. If T3​=40 N,T2​=?