In the figure shown, block A does not slide on block B. The normal contact force acting between two blocks is (assume all surfaces to be smooth)

Question

In the figure shown, block A does not slide on block B. The normal contact force acting between two blocks is (assume all surfaces to be smooth) (A) 4 N (B) 5 N (C) 10 N (D) 20 N

Tardigrade Admin · Accepted Answer

a = (8-4/4)=1 m/s2 8-Nsin37° =2× 1 (3N/5) = 6 ⇒ N = 10 N

Q. In the figure shown, block A does not slide on block B. The normal contact force acting between two blocks is (assume all surfaces to be smooth)

4 N

5 N

10 N

20 N

$a = \frac{8 - 4}{4} = 1 m / s^{2}$
$8 - N s in 3 7^{\circ} = 2 \times 1$
$\frac{3 N}{5} = 6 \Rightarrow N = 10 N$

Q. In the figure shown, block A does not slide on block B. The normal contact force acting between two blocks is (assume all surfaces to be smooth)

4 N

5 N

10 N

20 N

a=48−4​=1m/s2 8−Nsin37∘=2×1 53N​=6⇒N=10N

$a = \frac{8 - 4}{4} = 1 m / s^{2}$
$8 - N s in 3 7^{\circ} = 2 \times 1$
$\frac{3 N}{5} = 6 \Rightarrow N = 10 N$