In the figure, a sphere of radius 2 m rolls on a plank. The accelerations of the sphere and the plank are indicated. The value of angular acceleration is

Question

In the figure, a sphere of radius 2 m rolls on a plank. The accelerations of the sphere and the plank are indicated. The value of angular acceleration is <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-mciiqotiemfd.png" /> (A) 2rads- 2 (B) 4rads- 2 (C) 3rads- 2 (D) 1rads- 2

Tardigrade Admin · Accepted Answer

As the sphere rolls, the lowest point of the sphere should have the same acceleration as the plank. Hence, a1=αR-a2 2=2α -4 ⇒ α =3rads- 2

Q. In the figure, a sphere of radius $2 m$ rolls on a plank. The accelerations of the sphere and the plank are indicated. The value of angular acceleration is

$2 r a d s^{- 2}$

$4 r a d s^{- 2}$

$3 r a d s^{- 2}$

$1 r a d s^{- 2}$

As the sphere rolls, the lowest point of the sphere should have the same acceleration as the plank.
Hence, $a_{1} = α R - a_{2}$
$2 = 2 α - 4$
$\Rightarrow α = 3 r a d s^{- 2}$

Q. In the figure, a sphere of radius 2m rolls on a plank. The accelerations of the sphere and the plank are indicated. The value of angular acceleration is

2rads−2

4rads−2

3rads−2

1rads−2