Question

In the coordination compound, $K_4[Ni(CN{)}_4]$ oxidation state of nickel is

• A. $-1$
• B. $0$
• C. $+l$
• D. $+2$

Answer 1

Answer: (B)

$+1\times 4+x-1\times 4=0$
$4+x-4=0\Rightarrow x=0$ for Ni