In the circuit shown (figure), the cell is ideal. The coil has an inductance of 4 H and zero resistance. F is a fuse of zero resistance and will blow when the current through it reaches 5 A. The switch is closed at t=0. The fuse will blow

Question

In the circuit shown (figure), the cell is ideal. The coil has an inductance of 4 H and zero resistance. F is a fuse of zero resistance and will blow when the current through it reaches 5 A. The switch is closed at t=0. The fuse will blow (A) almost at once (B) after 2 s (C) after 5 s (D) after 10 s

Tardigrade Admin · Accepted Answer

E=L (d I/d t) or d I=(E/L) d t or I=(2/4) t=0.5 t ⇒ t=2 I=2 × 5=10 s

Q. In the circuit shown (figure), the cell is ideal. The coil has an inductance of $4 H$ and zero resistance. $F$ is a fuse of zero resistance and will blow when the current through it reaches $5 A$ . The switch is closed at $t = 0$ . The fuse will blow

almost at once

after 2 s

after 5 s

after 10 s

$E = L \frac{d I}{d t}$ or $d I = \frac{E}{L} d t$
or $I = \frac{2}{4} t = 0.5 t$
$\Rightarrow t = 2 I = 2 \times 5 = 10 s$

Q. In the circuit shown (figure), the cell is ideal. The coil has an inductance of 4H and zero resistance. F is a fuse of zero resistance and will blow when the current through it reaches 5A. The switch is closed at t=0. The fuse will blow