In the case of diffraction pattern due to a single slit, angular width of central max can be increased by

Question

In the case of diffraction pattern due to a single slit, angular width of central max can be increased by (A) decreasing the wavelength (B) increasing the slit width (C) increasing distance between slit and screen (D) decreasing the slit width

Tardigrade Admin · Accepted Answer

In case of single slit diffraction angular width of central maxima is given by θ = (2 λ/a) where a = width of slit, λ = wavelength of light θ can be increased by decreasing a.

Q. In the case of diffraction pattern due to a single slit, angular width of central max can be increased by

decreasing the wavelength

increasing the slit width

increasing distance between slit and screen

decreasing the slit width

In case of single slit diffraction angular width of central maxima is given by $θ = \frac{2 λ}{a}$
where a = width of slit,
$λ =$ wavelength of light
$θ$ can be increased by decreasing $a$ .

Q. In the case of diffraction pattern due to a single slit, angular width of central max can be increased by

decreasing the wavelength

increasing the slit width

increasing distance between slit and screen

decreasing the slit width

In case of single slit diffraction angular width of central maxima is given by θ=a2λ​ where a = width of slit, λ= wavelength of light θ can be increased by decreasing a.

In case of single slit diffraction angular width of central maxima is given by $θ = \frac{2 λ}{a}$
where a = width of slit,
$λ =$ wavelength of light
$θ$ can be increased by decreasing $a$ .