In the cannizzaro reaction given below 2 Ph - CHO -[ OH -] Ph - CH - OH + PhCO 2-the slowest step is

Question

In the cannizzaro reaction given below 2 Ph - CHO ->[ OH -] Ph - CH - OH + PhCO 2-the slowest step is (A) the attack of OH at the carbonyl group (B) the transfer of hydride ion to the carbonyl group (C) the abstraction of a proton from the carboxylic acid (D) the deprotonation of Ph - CH 2 OH

Tardigrade Admin · Accepted Answer

Transfer of hydride ion to the carbonyl group is the slowest or the rate determining step

underset overset+Ph - C H2OHPh- overset underset||OC-OH <=> [ Ph - overset underset||OC OH + ph - underset overset|H overset underset|O-C- H]

Q. In the cannizzaro reaction given below $2 P h - C H O O H^{-} P h - C H - O H + P h C O_{2}^{-}$ the slowest step is

the attack of $O H$ at the carbonyl group

the transfer of hydride ion to the carbonyl group

the abstraction of a proton from the carboxylic acid

the deprotonation of $P h - C H_{2} O H$

Transfer of hydride ion to the carbonyl group is the slowest or the rate determining step

$P h - C H_{2} O H + P h - C ∣∣ O - O H ⎣ ⎡ P h - C ∣∣ O O H + p h - H ∣ C ∣ O^{-} - H ⎦ ⎤$

Q. In the cannizzaro reaction given below 2Ph−CHO OH-​Ph−CH−OH+PhCO2−​the slowest step is

the attack of OH at the carbonyl group