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Tardigrade
Question
Chemistry
In the brown ring complex [Fe (H2O)5(NO)]SO4, nitric oxide behaves as
Q. In the brown ring complex
[
F
e
(
H
2
O
)
5
(
NO
)
]
S
O
4
,
nitric oxide behaves as
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A
N
O
+
B
neutral NO molecule
C
N
O
−
D
N
O
2
−
Solution:
In Fe-complexes, NO behaves as
N
O
+
.