Question

In sine wave, minimum distance between 2 particles always having same speed is

• A. $\frac{\lambda }{2}$
• B. $\frac{\lambda }{4}$
• C. $\frac{\lambda }{3}$
• D. $\lambda$

Answer 1

Answer: (A)

Sine wave
Particle velocity $v_p=\frac{dy}{dt}=$ slope of wave at that point.
At slope at A and B is zero. Hence there velocity at A and B will be same. Distance between A and B is $\frac{\lambda }{2}.$