Copper is the most noble of the first row transition metals and occurs in smali deposits in several countries. Ores of copper include chalcanthite ( CuSO 4 ⋅ 5 H 2 O ), atacamite ( Cu 2 Cl ( OH )3), cuprite ( Cu 2 O ), copper glance ( Cu 2 S ) and malachite ( Cu 2( OH )2 CO 3). However, 80 % of the world copper production comes from the ore chalcopyrite ( CuFeS 2). The extraction of copper from chalcopyrite involves partial roasting, removal of iron and self-reduction. In self-reduction. the reducing species is (1) S (2) O 2- (3) S 2- (4) SO 2

Question

Copper is the most noble of the first row transition metals and occurs in smali deposits in several countries. Ores of copper include chalcanthite ( CuSO 4 ⋅ 5 H 2 O ), atacamite ( Cu 2 Cl ( OH )3), cuprite ( Cu 2 O ), copper glance ( Cu 2 S ) and malachite ( Cu 2( OH )2 CO 3). However, 80 % of the world copper production comes from the ore chalcopyrite ( CuFeS 2). The extraction of copper from chalcopyrite involves partial roasting, removal of iron and self-reduction. In self-reduction. the reducing species is (1) S (2) O 2- (3) S 2- (4) SO 2 (A) S (B) O2 (C) S2- (D) SO2

Tardigrade Admin · Accepted Answer

Cu2S+2Cu2O2arrow 6Cu+SO2 In Cu2S, sulphur is S2- and in SO2, sulphur is in +4 state. Hence, S2- is acting as reducing agent.

S

$O^{2}$

$S^{2 -}$

$S O_{2}$

$C u_{2} S + 2 C u_{2} O_{2} \to 6 C u + S O_{2}$
In $C u_{2} S$ , sulphur is $S^{2 -}$ and in $S O_{2}$ , sulphur is in $+ 4$ state. Hence, $S^{2 -}$ is acting as reducing agent.

S

O2

S2−

SO2​

Cu2​S+2Cu2​O2​→6Cu+SO2​ In Cu2​S, sulphur is S2− and in SO2​, sulphur is in +4 state. Hence, S2− is acting as reducing agent.

$O^{2}$

$S^{2 -}$

$S O_{2}$

$C u_{2} S + 2 C u_{2} O_{2} \to 6 C u + S O_{2}$
In $C u_{2} S$ , sulphur is $S^{2 -}$ and in $S O_{2}$ , sulphur is in $+ 4$ state. Hence, $S^{2 -}$ is acting as reducing agent.