In nitroprusside ion, the iron and NO exist as Fe2+ and NO+ rather than Fe3+ and NO . These forms can be differentiated by

Question

In nitroprusside ion, the iron and NO exist as Fe2+ and NO+ rather than Fe3+ and NO . These forms can be differentiated by (A) estimating the concentration of iron (B) measuring the concentration of CN-  (C) measuring the solid state magnetic moment (D) thermally decomposing the compound

Tardigrade Admin · Accepted Answer

The existance of Fe2+ and NO+ in nitroprusside ion, [Fe(CN)5NO]2- can be established by measuring the magnetic moment of the solid compound which should correspond to (Fe2+=3d6) four unpaired electrons.

Q. In nitroprusside ion, the iron and NO exist as $F e^{2 +}$ and $N O^{+}$ rather than $F e^{3 +}$ and $NO$ . These forms can be differentiated by

estimating the concentration of iron

measuring the concentration of $C N^{-}$

measuring the solid state magnetic moment

thermally decomposing the compound

The existance of $F e^{2 +}$ and $N O^{+}$ in nitroprusside ion, $[F e (CN)_{5} NO]^{2 -}$ can be established by measuring the magnetic moment of the solid compound which should correspond to $(F e^{2 +} = 3 d^{6})$ four unpaired electrons.

Q. In nitroprusside ion, the iron and NO exist as Fe2+ and NO+ rather than Fe3+ and NO . These forms can be differentiated by