Q. In Nessler s reagent, the ion present is

1280 238 The d-and f-Block Elements Report Error

A

$H g I^{2 -}$

20%

B

$H g I_{4}^{2 -}$

28%

C

$H g^{+}$

33%

D

$H g^{2 +}$

18%

Solution:

Nessler's reagent is $K_{2} H g I_{4}$ . The ion present is $H g I_{4}^{2 -}$ and $K^{+}$ .