In NaHCO3 solid, two bicarbonate ions are bonded through strong H-bonds as shown below The four O-O distances marked are 'a' 'b' c' 'd'. The correct order of these distances is

Question

In NaHCO3 solid, two bicarbonate ions are bonded through strong H-bonds as shown below <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/df218e6d94c86a370056ee6d6c42885f-.png" /> The four O-O distances marked are 'a' 'b' c' 'd'. The correct order of these distances is (A) a < c < b < d (B) a < b < d < c (C) a < d < c < b (D) b < d < a < c

Tardigrade Admin · Accepted Answer

From the given figure it is clear a - being strong H-bond (minimum distance)

Q. In $N a H C O_{3}$ solid, two bicarbonate ions are bonded through strong H-bonds as shown below

The four $O - O$ distances marked are ' $a$ '' $b$ ' $c$ ' & ' $d$ '. The correct order of these distances is

a < c < b < d

a < b < d < c

a < d < c < b

b < d < a < c

From the given figure it is clear a - being strong $H$ -bond (minimum distance)

Q. In NaHCO3​ solid, two bicarbonate ions are bonded through strong H-bonds as shown below The four O−O distances marked are 'a''b' c' & 'd'. The correct order of these distances is