In n-type semiconductor when all donor states are filled, then the net charge density in the donor states becomes

Question

In n-type semiconductor when all donor states are filled, then the net charge density in the donor states becomes (A) 1 (B) > 1 (C) < 1, but not zero (D) zero

Tardigrade Admin · Accepted Answer

If all the donor states in n-type semiconductor are filled, the number of electrons in donor states will increase. Due to it, the charge density in donor states will become more than one.

Q. In $n$ -type semiconductor when all donor states are filled, then the net charge density in the donor states becomes

$1$

$> 1$

$< 1$ , but not zero

zero

If all the donor states in n-type semiconductor are filled, the number of electrons in donor states will increase. Due to it, the charge density in donor states will become more than one.

Q. In n-type semiconductor when all donor states are filled, then the net charge density in the donor states becomes

1

>1

<1, but not zero

zero

If all the donor states in n-type semiconductor are filled, the number of electrons in donor states will increase. Due to it, the charge density in donor states will become more than one.

Q. In $n$ -type semiconductor when all donor states are filled, then the net charge density in the donor states becomes

$1$

$> 1$

$< 1$ , but not zero