Question

In $K_4[Fe(CN{)}_6]$ the EAN of $Fe$ is

• A. $33$
• B. $35$
• C. $36$
• D. $26$

Answer 1

Answer: (C)

EAN = Atomic number - Oxidation state + 2 $\times$ number of
Ligands $=26-2+2(6)=36.$