In hexacyanomanganate (II) ion the Mn-atom assumes d2sp3-hybrid state. The number of unpaired electrons in the complex is:

Question

In hexacyanomanganate (II) ion the Mn-atom assumes d2sp3-hybrid state. The number of unpaired electrons in the complex is: (A) 2 (B) 3 (C) 0 (D) 1

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Mn in Mn(CN)64- has configuration: ' <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/eebf25ad97d79487a38eace7994d2342-.jpeg" />

Q. In hexacyanomanganate (II) ion the $M n$ -atom assumes $d^{2} s p^{3}$ -hybrid state. The number of unpaired electrons in the complex is:

$2$

$3$

$0$

$1$

Mn in Mn $(CN)_{6}^{4 -}$ has configuration:
'

Q. In hexacyanomanganate (II) ion the Mn-atom assumes d2sp3-hybrid state. The number of unpaired electrons in the complex is:

2

3

0

1

Mn in Mn(CN)64−​ has configuration: '

Q. In hexacyanomanganate (II) ion the $M n$ -atom assumes $d^{2} s p^{3}$ -hybrid state. The number of unpaired electrons in the complex is:

$2$

$3$

$0$

$1$

Mn in Mn $(CN)_{6}^{4 -}$ has configuration:
'