In Freundlich adsorption isotherm at moderate pressure, the extent of adsorption (( x / m )) is directly proportional to Px. The value of x is

Question

In Freundlich adsorption isotherm at moderate pressure, the extent of adsorption (( x / m )) is directly proportional to Px. The value of x is (A) zero (B) (1/ n ) (C) 1 (D) ∞

Tardigrade Admin · Accepted Answer

As per Freundlich adsorption isotherm (( x / m ))= KP (1/ n ) arrow x =(1/ n )

Q. In Freundlich adsorption isotherm at moderate pressure, the extent of adsorption $(\frac{x}{m})$ is directly proportional to $P x$ . The value of $x$ is

zero

$\frac{1}{n}$

1

$\infty$

As per Freundlich adsorption isotherm

$(\frac{x}{m}) = K P^{\frac{1}{n}} \to x = \frac{1}{n}$

Q. In Freundlich adsorption isotherm at moderate pressure, the extent of adsorption (mx​) is directly proportional to Px. The value of x is

zero

n1​

1

∞

As per Freundlich adsorption isotherm (mx​)=KPn1​→x=n1​

Q. In Freundlich adsorption isotherm at moderate pressure, the extent of adsorption $(\frac{x}{m})$ is directly proportional to $P x$ . The value of $x$ is

$\frac{1}{n}$

$\infty$

As per Freundlich adsorption isotherm

$(\frac{x}{m}) = K P^{\frac{1}{n}} \to x = \frac{1}{n}$