In CS2, sulphur atoms are associated to form colloidal sol. 2.56 g of sulphur colloidal sol in 100 g CS2 shows osmotic pressure of 2.463 atm at 300 K. How many sulphur atoms are associated in colloidal sol? (Solution constant = 0.0821 L atm mol -1 K-1).

Question

In CS2, sulphur atoms are associated to form colloidal sol. 2.56 g of sulphur colloidal sol in 100 g CS2 shows osmotic pressure of 2.463 atm at 300 K. How many sulphur atoms are associated in colloidal sol? (Solution constant = 0.0821 L atm mol -1 K-1). (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

underset textMolar mass 32xxS leftharpoons Sx (associated colloidal sol) Osmotic pressure, π = MRT = (n/V)RT = (wRT/mV) Molar mass of Sx = m (Sx) = (wRT/π V) <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/fccb1717da0901ad15cce4a91679d439-.png" /> = (2.56 ×0.0821 ×300/2.463 ×0.01) = 256 ∴ 32 x = 256 x = 8

Q. In $C S_{2}$ , sulphur atoms are associated to form colloidal sol. $2.56 g$ of sulphur colloidal sol in $100 g C S_{2}$ shows osmotic pressure of $2.463$ atm at $300 K$ . How many sulphur atoms are associated in colloidal sol? (Solution constant $= 0.0821 L$ atm mol $^{- 1} K^{- 1}$ ).

$Molar mass 32x x S ⇌ S_{x}$ (associated colloidal sol) Osmotic pressure,
$π = MRT = \frac{n}{V} RT = \frac{wRT}{mV}$
Molar mass of $S_{x} = m (S_{x}) = \frac{wRT}{πV}$

$= \frac{2.56 \times 0.0821 \times 300}{2.463 \times 0.01} = 256$
$∴ 32 x = 256$
$x = 8$

Q. In CS2​, sulphur atoms are associated to form colloidal sol. 2.56g of sulphur colloidal sol in 100gCS2​ shows osmotic pressure of 2.463 atm at 300K. How many sulphur atoms are associated in colloidal sol? (Solution constant =0.0821L atm mol −1K−1).

Molar mass 32xxS⇌Sx​​ (associated colloidal sol) Osmotic pressure, π=MRT=Vn​RT=mVwRT​ Molar mass of Sx​=m(Sx​)=πVwRT​ =2.463×0.012.56×0.0821×300​=256 ∴32x=256 x=8

Q. In $C S_{2}$ , sulphur atoms are associated to form colloidal sol. $2.56 g$ of sulphur colloidal sol in $100 g C S_{2}$ shows osmotic pressure of $2.463$ atm at $300 K$ . How many sulphur atoms are associated in colloidal sol? (Solution constant $= 0.0821 L$ atm mol $^{- 1} K^{- 1}$ ).

$Molar mass 32x x S ⇌ S_{x}$ (associated colloidal sol) Osmotic pressure,
$π = MRT = \frac{n}{V} RT = \frac{wRT}{mV}$
Molar mass of $S_{x} = m (S_{x}) = \frac{wRT}{πV}$

$= \frac{2.56 \times 0.0821 \times 300}{2.463 \times 0.01} = 256$
$∴ 32 x = 256$
$x = 8$