In an RC circuit fed with AC, capacitive reactance is equal to the resistance (R) used in the circuit. Then, phase angle between current and voltage and impedance of the circuit are respectively

Question

In an RC circuit fed with AC, capacitive reactance is equal to the resistance (R) used in the circuit. Then, phase angle between current and voltage and impedance of the circuit are respectively (A) 0° , 2R  (B) 45° , √2 R  (C) 0° , √2R  (D) 45° , 5R

Tardigrade Admin · Accepted Answer

Capacitive reaetance, XC = R φ= tan-1 ((XC/R)) = tan -1(1)=45° Impedance of circuit, Z = √XC2 +R2 = √R2+ R2 = √2 R

Q. In an $RC$ circuit fed with $A C$ , capacitive reactance is equal to the resistance $(R)$ used in the circuit. Then, phase angle between current and voltage and impedance of the circuit are respectively

$0^{\circ}, 2 R$

$4 5^{\circ}, 2 R$

$0^{\circ}, 2 R$

$4 5^{\circ}, 5 R$

Capacitive reaetance, $X_{C} = R$
$ϕ = tan^{- 1} (\frac{X _{C}}{R}) = tan^{- 1} (1) = 4 5^{\circ}$
Impedance of circuit,
$Z = X_{C}^{2} + R^{2} = R^{2} + R^{2} = 2 R$

Q. In an RC circuit fed with AC, capacitive reactance is equal to the resistance (R) used in the circuit. Then, phase angle between current and voltage and impedance of the circuit are respectively

0∘,2R

45∘,2​R

0∘,2R​

45∘,5R

Capacitive reaetance, XC​=R ϕ=tan−1(RXC​​)=tan−1(1)=45∘ Impedance of circuit, Z=XC2​+R2​=R2+R2​=2​R

Q. In an $RC$ circuit fed with $A C$ , capacitive reactance is equal to the resistance $(R)$ used in the circuit. Then, phase angle between current and voltage and impedance of the circuit are respectively

$0^{\circ}, 2 R$

$4 5^{\circ}, 2 R$

$0^{\circ}, 2 R$

$4 5^{\circ}, 5 R$

Capacitive reaetance, $X_{C} = R$
$ϕ = tan^{- 1} (\frac{X _{C}}{R}) = tan^{- 1} (1) = 4 5^{\circ}$
Impedance of circuit,
$Z = X_{C}^{2} + R^{2} = R^{2} + R^{2} = 2 R$