In an intrinsic semiconductor:

Question

In an intrinsic semiconductor: (A)  ne>nh  (B)  nh>ne  (C)  ne=nh  (D)  ne=nh=0

Tardigrade Admin · Accepted Answer

Pure semiconductors are intrinsic semiconductors. They have not any impurity. Hence, number of electrons in the conduction band is equal to the number of holes in valence band. It means ne=nh .

Q. In an intrinsic semiconductor:

$n_{e} > n_{h}$

$n_{h} > n_{e}$

$n_{e} = n_{h}$

$n_{e} = n_{h} = 0$

Pure semiconductors are intrinsic semiconductors. They have not any impurity. Hence, number of electrons in the conduction band is equal to the number of holes in valence band. It means $n_{e} = n_{h}$ .

Q. In an intrinsic semiconductor:

ne​>nh​

nh​>ne​

ne​=nh​

ne​=nh​=0

Pure semiconductors are intrinsic semiconductors. They have not any impurity. Hence, number of electrons in the conduction band is equal to the number of holes in valence band. It means ne​=nh​ .

$n_{e} > n_{h}$

$n_{h} > n_{e}$

$n_{e} = n_{h}$

$n_{e} = n_{h} = 0$

Pure semiconductors are intrinsic semiconductors. They have not any impurity. Hence, number of electrons in the conduction band is equal to the number of holes in valence band. It means $n_{e} = n_{h}$ .