In an experiment on photoelectric effect the frequency V of the incident light is plotted against the stopping potential V0 . The work function of the photoelectric surface is given by (e is electronic charge)

Question

In an experiment on photoelectric effect the frequency V of the incident light is plotted against the stopping potential V0 . The work function of the photoelectric surface is given by (e is electronic charge) (A) O B × e in eV (B) O B in volt (C) O A in eV (D) The slope of the line A B

Tardigrade Admin · Accepted Answer

Using Einstein's equation, V0=((h/e)) v-(W0/e) Comparing this equation with y=m x +c, we get intercept on -V0 axis as -(W0/e). ⇒ O B=(W0/e) ⇒ W0=O B × e

Q. In an experiment on photoelectric effect the frequency $V$ of the incident light is plotted against the stopping potential $V_{0} .$ The work function of the photoelectric surface is given by $(e$ is electronic charge)

$OB \times e$ in $e V$

$OB$ in volt

$O A$ in $e V$

The slope of the line $A B$

Using Einstein's equation, $V_{0} = (\frac{h}{e}) v - \frac{W _{0}}{e}$
Comparing this equation with $y = m x + c$ ,
we get intercept on $- V_{0}$ axis as $- \frac{W _{0}}{e}$ .
$\Rightarrow OB = \frac{W _{0}}{e}$
$\Rightarrow W_{0} = OB \times e$

Q. In an experiment on photoelectric effect the frequency V of the incident light is plotted against the stopping potential V0​. The work function of the photoelectric surface is given by (e is electronic charge)

OB×e in eV

OB in volt

OA in eV

The slope of the line AB