In an acidified solution of K2Cr2O7 ,H2O2 is added. Then

Question

In an acidified solution of K2Cr2O7 ,H2O2 is added. Then (A) solution turns green due to formation of Cr2O3 (B) solution turns yellow due to formation of K2CrO4 (C) a blue coloured compound CrO(O2)2 is formed (D) solution gives green precipitate of Cr ( OH )3

Tardigrade Admin · Accepted Answer

Hydrogen peroxide acts as an oxidising as well as a reducing agent in both acidic and alkaline media.

When

H_{2} O_{2}

is added to an acidified potassium dichromate solution, the blue coloured compound

C r O_{5}

or

C r O (O_{2})_{2}

is formed. The chemical reaction is as follows

C r_{2} O_{7}^{2 -} + 2 H^{+} + 4 H_{2} O_{2} \to 2 C r O (O_{2})_{2} + 5 H_{2} O

Q. In an acidified solution of $K_{2} C r_{2} O_{7}$ $, H_{2} O_{2}$ is added. Then

solution turns green due to formation of $C r_{2} O_{3}$

solution turns yellow due to formation of $K_{2} C r O_{4}$

a blue coloured compound $C r O (O_{2})_{2}$ is formed

solution gives green precipitate of $C r (O H)_{3}$

Q. In an acidified solution of K2​Cr2​O7​ ,H2​O2​ is added. Then

solution turns green due to formation of Cr2​O3​

solution turns yellow due to formation of K2​CrO4​

a blue coloured compound CrO(O2​)2​ is formed

solution gives green precipitate of Cr(OH)3​

Q. In an acidified solution of $K_{2} C r_{2} O_{7}$ $, H_{2} O_{2}$ is added. Then

solution turns green due to formation of $C r_{2} O_{3}$

solution turns yellow due to formation of $K_{2} C r O_{4}$

a blue coloured compound $C r O (O_{2})_{2}$ is formed

solution gives green precipitate of $C r (O H)_{3}$