Question

In acidic medium, $Mn{O}_4^{2-}$

• A. disproportionates to $Mn{O}_2$ and $Mn{O}_4^{-}$
• B. is oxidised to $Mn{O}_4^{-}$
• C. is reduced to $Mn{O}_2$
• D. is reduced to $M{n}^{2+}$.

Answer 1

Answer: (A)

$Mn{O}_4^{2-}$ disproportionates in acidic medium as follows:
$3Mn{O}_4^{2-}+4H^{+}⟶2Mn{O}_4^{-}+Mn{O}_2+2H_{2}O$