Question

In a zero order reaction for every $10^{\circ }$C rise of temperature, the rate is doubled. If the temperature is increased from $10^{\circ }$C to $100^{\circ }$C, the rate of the reaction will become .

• A. 256 times
• B. 512 times
• C. 64 times
• D. 128 times
• E. 100 times

Answer 1

Answer: (B)

For 10${}^{\circ }$ rise in temperature, n = 1
so rate = $2^n=2^1=2$
When temperature is increased from 10${}^{\circ }$C to 100${}^{\circ }$C, change in temperature
$=100-10=$90${}^{\circ }$C
i.e. $n=9$
So, rate = $2^9$ = 512 times
Alternate method with every 10${}^{\circ }$ rise in temperature, rate becomes double,
so $\frac{r^{\prime }}{r}=2^{\left(\frac{100-10}{10}\right)}=2^9=$ 512 times.