In a Youngs double slit experiment an electron beam is used to obtain interference pattern. If the speed of electron decreases then

Question

In a Youngs double slit experiment an electron beam is used to obtain interference pattern. If the speed of electron decreases then (A) distance between two consecutive fringes remains the same (B) distance between two consecutive fringes decreases (C) distance between two consecutive fringes increases (D) none of these

Tardigrade Admin · Accepted Answer

Fringe width, β = (λ D/d); Also, λ = (h/mv) Here h is planck's constant. This wavelength is inversely proportional to the velocity. Hence, the fringe width increases with decrease in electron speed.

Q. In a Youngs double slit experiment an electron beam is used to obtain interference pattern. If the speed of electron decreases then

distance between two consecutive fringes remains the same

distance between two consecutive fringes decreases

distance between two consecutive fringes increases

none of these

Fringe width, $β = \frac{λ D}{d}$ ; Also, $λ = \frac{h}{m v}$
Here $h$ is planck's constant. This wavelength is inversely proportional to the velocity. Hence, the fringe width increases with decrease in electron speed.

Q. In a Youngs double slit experiment an electron beam is used to obtain interference pattern. If the speed of electron decreases then

distance between two consecutive fringes remains the same

distance between two consecutive fringes decreases

distance between two consecutive fringes increases

none of these

Fringe width, β=dλD​; Also, λ=mvh​ Here h is planck's constant. This wavelength is inversely proportional to the velocity. Hence, the fringe width increases with decrease in electron speed.

Fringe width, $β = \frac{λ D}{d}$ ; Also, $λ = \frac{h}{m v}$
Here $h$ is planck's constant. This wavelength is inversely proportional to the velocity. Hence, the fringe width increases with decrease in electron speed.