In a Young's double slit experiment, the slits are placed 0.320 mm apart. Light of wavelength λ = 500 nm is incident on the slits.The total number of bright fringes that are observed in the angular range -30° le θ le 30° is :

Question

In a Young's double slit experiment, the slits are placed 0.320 mm apart. Light of wavelength λ = 500 nm is incident on the slits.The total number of bright fringes that are observed in the angular range -30° le θ le 30° is : (A) 320 (B) 641 (C) 321 (D) 640

Tardigrade Admin · Accepted Answer

Pam difference d sin θ= n λ where d = seperation of slits λ = wave length n = no. of maximas 0.32 × 10-3 sin 30 = n × 500 × 10-9 n = 320 Hence total no. of maximas observed in angular range -30° le θ le 30° is maximas = 320 + 1 + 320 = 641

Q. In a Young's double slit experiment, the slits are placed 0.320mm apart. Light of wavelength λ=500nm is incident on the slits.The total number of bright fringes that are observed in the angular range −30∘≤θ≤30∘ is :

320

641

321

640

Pam difference dsinθ=nλ where d = seperation of slits λ = wave length n=no. of maximas 0.32×10−3sin30=n×500×10−9 n=320 Hence total no. of maximas observed in angular range −30∘≤θ≤30∘ is maximas = 320+1+320=641

Q. In a Young's double slit experiment, the slits are placed $0.320 mm$ apart. Light of wavelength $λ = 500 nm$ is incident on the slits.The total number of bright fringes that are observed in the angular range $- 3 0^{\circ} \leq θ \leq 3 0^{\circ}$ is :