In a triode valve, the plate resistance is 10000 Ω and the anode load resistance is 30000 Ω. If the amplification factor is 36 , then the voltage gain is :

Question

In a triode valve, the plate resistance is 10000 Ω and the anode load resistance is 30000 Ω. If the amplification factor is 36 , then the voltage gain is : (A) 9 (B) 27 (C) 36 (D) 108

Tardigrade Admin · Accepted Answer

Voltage amplification (gain) is given by

A = \frac{μ}{1 + \frac{r _{p}}{R _{L}}}

where

μ

is amplification factor,

r_{p}

is plate resistance and

R_{L}

is load resistance.
Given,

μ = 36, r_{p} = 10000 Ω, R_{L} = 30000 Ω

Putting in the relation, we obtain

A = \frac{36}{1 + \frac{10000}{30000}}

= \frac{36}{1 + \frac{1}{3}}

= \frac{36 \times 3}{4}

= 27

Q. In a triode valve, the plate resistance is 10000Ω and the anode load resistance is 30000Ω. If the amplification factor is 36 , then the voltage gain is :

9

27

36

108

Voltage amplification (gain) is given by A=1+RL​rp​​μ​ where μ is amplification factor, rp​ is plate resistance and RL​ is load resistance. Given, μ=36,rp​=10000Ω,RL​=30000Ω Putting in the relation, we obtain A=1+3000010000​36​ =1+31​36​ =436×3​ =27

Q. In a triode valve, the plate resistance is $10000 Ω$ and the anode load resistance is $30000 Ω$ . If the amplification factor is $36$ , then the voltage gain is :