In a transistor if (IC/IE)=α and (IC/IB)=β . If α varies between (20/21) and (100/101), then the value of β lies between

Question

In a transistor if (IC/IE)=α and (IC/IB)=β . If α varies between (20/21) and (100/101), then the value of β lies between (A) 1-10 (B) 0.95-0.99 (C) 20-100 (D) 200-300

Tardigrade Admin · Accepted Answer

β=(α/1-α) β1=((20/21)/1-(20)21)=20, β2=((100/101)/1-(100)101)=100 The value of β lies between 20-100.

Q. In a transistor if $\frac{I _{C}}{I _{E}} = α$ and $\frac{I _{C}}{I _{B}} = β .$ If $α$ varies between $\frac{20}{21}$ and $\frac{100}{101}$ , then the value of $β$ lies between

1-10

0.95-0.99

20-100

200-300

$β = \frac{α}{1 - α}$
$β_{1} = \frac{\frac{20}{21}}{1 - \frac{20}{21}} = 20,$
$β_{2} = \frac{\frac{100}{101}}{1 - \frac{100}{101}} = 100$
The value of $β$ lies between $20 - 100$ .

Q. In a transistor if IE​IC​​=α and IB​IC​​=β. If α varies between 2120​ and 101100​, then the value of β lies between