In a series LCR circuit, the potential drop across L, C and R respectively are 40 V, 120 V and 60 V. Then the source voltage is

Question

In a series LCR circuit, the potential drop across L, C and R respectively are 40 V, 120 V and 60 V. Then the source voltage is (A) 220 V (B) 160 V (C) 180 V (D) 100 V

Tardigrade Admin · Accepted Answer

In series L-C-R circuit, the source voltage Here, V =√VR2+(VL-VC)2 VR =60 V ⇒ VL=40 V VC =120 V V =√(60)2+(40-120)2 =√(60)2+(-80)2=√3600+6400 =√10000=100 V

Q. In a series $L CR$ circuit, the potential drop across $L, C$ and $R$ respectively are $40 V$ , $120 V$ and $60 V$ . Then the source voltage is

220 V

160 V

180 V

100 V

In series $L - C - R$ circuit, the source voltage
Here, $V = V_{R}^{2} + (V_{L} - V_{C})^{2}$
$V_{R} = 60 V \Rightarrow V_{L} = 40 V$
$V_{C} = 120 V$
$V = (60)^{2} + (40 - 120)^{2}$
$= (60)^{2} + (- 80)^{2} = 3600 + 6400$
$= 10000 = 100 V$

Q. In a series LCR circuit, the potential drop across L,C and R respectively are 40V, 120V and 60V. Then the source voltage is