In a room there are 6 couples. Out of them if 4 are selected at random, the probability that they may be couples is

Question

In a room there are 6 couples. Out of them if 4 are selected at random, the probability that they may be couples is (A) (4/33) (B) (2/33) (C) (1/33) (D) (3/33)

Tardigrade Admin · Accepted Answer

n (S) = 12C4, n(E) = 6C2,P(E) = (1/33)

Q. In a room there are 6 couples. Out of them if 4 are selected at random, the probability that they may be couples is

$\frac{4}{33}$

$\frac{2}{33}$

$\frac{1}{33}$

$\frac{3}{33}$

$n (S) =^{12} C_{4}, n (E) =^{6} C_{2}, P (E) = \frac{1}{33}$

Q. In a room there are 6 couples. Out of them if 4 are selected at random, the probability that they may be couples is

334​

332​

331​

333​

n(S)=12C4​,n(E)=6C2​,P(E)=331​

$\frac{4}{33}$

$\frac{2}{33}$

$\frac{1}{33}$

$\frac{3}{33}$

$n (S) =^{12} C_{4}, n (E) =^{6} C_{2}, P (E) = \frac{1}{33}$