In a resonance tube experiment when the tube is filled with water up to height of 17.0 cm from bottom, it resonates with a given tuning fork. When the water level is raised the next resonance with the same tuning fork occurs at a height of 24.5 cm. If the velocity of sound in air is 330 m / s, the tuning fork frequency is:

Question

In a resonance tube experiment when the tube is filled with water up to height of 17.0 cm from bottom, it resonates with a given tuning fork. When the water level is raised the next resonance with the same tuning fork occurs at a height of 24.5 cm. If the velocity of sound in air is 330 m / s, the tuning fork frequency is: (A) 1100 Hz (B) 3300 Hz (C) 2200 Hz (D) 550 Hz

Tardigrade Admin · Accepted Answer

⇒ λ=2(l2-l1) ⇒ 2 ×(24.5-17) ⇒ 2 × 7.5=15 cm v = f λ ⇒ 330=λ × 15 × 10-2 λ=(330/15) × 100 ⇒ (1100 × 100/5) ⇒ 2200 Hz

$1100 Hz$

$3300 Hz$

$2200 Hz$

$550 Hz$

$\Rightarrow λ = 2 (l_{2} - l_{1})$
$\Rightarrow 2 \times (24.5 - 17)$
$\Rightarrow 2 \times 7.5 = 15 c m$
& $v = f λ$
$\Rightarrow 330 = λ \times 15 \times 1 0^{- 2}$
$λ = \frac{330}{15} \times 100$
$\Rightarrow \frac{1100 \times 100}{5}$
$\Rightarrow 2200 Hz$

1100Hz

3300Hz

2200Hz

550Hz

⇒λ=2(l2​−l1​) ⇒2×(24.5−17) ⇒2×7.5=15cm & v=fλ ⇒330=λ×15×10−2 λ=15330​×100 ⇒51100×100​ ⇒2200Hz

$1100 Hz$

$3300 Hz$

$2200 Hz$

$550 Hz$

$\Rightarrow λ = 2 (l_{2} - l_{1})$
$\Rightarrow 2 \times (24.5 - 17)$
$\Rightarrow 2 \times 7.5 = 15 c m$
& $v = f λ$
$\Rightarrow 330 = λ \times 15 \times 1 0^{- 2}$
$λ = \frac{330}{15} \times 100$
$\Rightarrow \frac{1100 \times 100}{5}$
$\Rightarrow 2200 Hz$