In a resonance pipe the first and second resonance are obtained at depths text22 text.7 cm and text70 text.2 cm respectively. What will be the end correction?

Question

In a resonance pipe the first and second resonance are obtained at depths text22 text.7 cm and text70 text.2 cm respectively. What will be the end correction? (A)  text1 .0 text5 cm (B)  text115 text.5 cm (C)  text92 text.5 cm (D)  text113 text.5 cm

Tardigrade Admin · Accepted Answer

For the end correction x , Longrightarrow x=(l2 - 3 l1/2) =(70.2 - 3 × 22.7/2)=1.05 cm

Q. In a resonance pipe the first and second resonance are obtained at depths $22 .7 cm$ and $70 .2 cm$ respectively. What will be the end correction?

$1 .0 5 cm$

$115 .5 cm$

$92 .5 cm$

$113 .5 cm$

For the end correction $x$ ,
$⟹ x = \frac{l _{2} - 3 l _{1}}{2}$
$= \frac{70.2 - 3 \times 22.7}{2} = 1.05 c m$

Q. In a resonance pipe the first and second resonance are obtained at depths 22.7 cm and 70.2 cm respectively. What will be the end correction?

1.05 cm

115.5 cm

92.5 cm

113.5 cm