In a radioactive decay chain, 23290Th nucleus decays to 21292Pb nucleus. Let Nα and Nβ be the number of alpha and β- particles, respectively, emitted in this decay process. Which of the following statements is (are) true?

Question

In a radioactive decay chain, 23290Th nucleus decays to 21292Pb nucleus. Let Nα and Nβ be the number of alpha and β- particles, respectively, emitted in this decay process. Which of the following statements is (are) true? (A) Nα = 5  (B) Nα = 6  (C) Nβ = 2 (D) Nβ = 4

Tardigrade Admin · Accepted Answer

23290Th Th is converting into 21282Pb Change in mass number (A) = 20 ∴ no of α particle = (20/4) = 5 Due to 5 α particle, z will change by 10 unit. Since given change is 8, therefore no. of β particle is 2

Q. In a radioactive decay chain, $_{90}^{232} T h$ nucleus decays to $_{92}^{212} P b$ nucleus. Let $N_{α}$ and $N_{β}$ be the number of $a lp ha$ and $β^{-}$ particles, respectively, emitted in this decay process. Which of the following statements is (are) true?

$N_{α} = 5$

$N_{α} = 6$

$N_{β} = 2$

$N_{β} = 4$

$_{90}^{232} T h$ Th is converting into $_{82}^{212} P b$
Change in mass number (A) = 20
$∴$ no of $α$ particle $= \frac{20}{4} = 5$
Due to $5 α$ particle, z will change by 10 unit.
Since given change is 8, therefore no. of $β$ particle is 2

Q. In a radioactive decay chain, 90232​Th nucleus decays to 92212​Pb nucleus. Let Nα​ and Nβ​ be the number of alpha and β− particles, respectively, emitted in this decay process. Which of the following statements is (are) true?

Nα​=5

Nα​=6

Nβ​=2

Nβ​=4