In a radioactive decay, an element ZXA emits four α-particles, three β-particles and eight gamma photons. The atomic number and mass number of the resulting final nucleus are

Question

In a radioactive decay, an element ZXA emits four α-particles, three β-particles and eight gamma photons. The atomic number and mass number of the resulting final nucleus are (A) Z-11, A-16 (B) Z-5, A-13 (C) Z-5, A-16 (D) Z - 8, A - 13

Tardigrade Admin · Accepted Answer

After nα α -decays and nβ β-decays, the respective atomic number and mass number of resulting nucleus are given by Z'=Z-2 nα+n0=Z-8+3=Z-5 and A'=A-4 nα=A-16

Q. In a radioactive decay, an element $_{Z} X^{A}$ emits four $α$ -particles, three $β$ -particles and eight gamma photons. The atomic number and mass number of the resulting final nucleus are

$Z - 11, A - 16$

$Z - 5, A - 13$

$Z - 5, A - 16$

$Z - 8, A - 13$

After $n_{α}$ $α$ -decays and $n_{β}$ $β$ -decays, the respective atomic number and mass number of resulting nucleus are given by
$Z^{'} = Z - 2 n_{α} + n_{0} = Z - 8 + 3 = Z - 5$
and $A^{'} = A - 4 n_{α} = A - 16$

Q. In a radioactive decay, an element Z​XA emits four α-particles, three β-particles and eight gamma photons. The atomic number and mass number of the resulting final nucleus are

Z−11,A−16

Z−5,A−13

Z−5,A−16

Z−8,A−13