Question

In a population of 1000 individuals 360 belong to genotype AA, 480 to Aa and the remaining 160 to aa. Based on this data, the frequency of allele A in the population is :-

• A. 0.04
• B. 0.5
• C. 0.6
• D. 0.7

Answer 1

Answer: (C)

According to Hardy-Weinberg principle (p+q)² = p² + 2pq + q² = 1
where, p = The frequency of allele 'A'
q = The frequency of allele 'a'
p² = The frequency of individual 'AA'
q² = The frequency of individual 'aa'
2pq = The frequency of individual Aa (AA) P² 360 out of 1000 individual. or p²=36 out of 100.
q² = 160 out of 1000 or q² = 16 out of 100.
So, $q=\sqrt{0.16}=0.4$
As p + q = 1 So, p is 0.6