In a pond of water, a flame is held 2m above the surface of the water. A fish is at depth of 4m from the water surface. Refractive index of water is (4/3) . The apparent height of the flame from the eyes of fish is -

Question

In a pond of water, a flame is held 2m above the surface of the water. A fish is at depth of 4m from the water surface. Refractive index of water is (4/3) . The apparent height of the flame from the eyes of fish is - (A) 5.5m (B) 6 m (C) (8/3) m (D) (20/3) m

Tardigrade Admin · Accepted Answer

Apparent height of flame above water surface. hâ²= μ h=(4/3)× 2=(8/3)m Therefore, apparent height of the flame from the eye of fish =d+hâ²=4+(8/3)=(20/3)m

Q. In a pond of water, a flame is held $2 m$ above the surface of the water. A fish is at depth of $4 m$ from the water surface. Refractive index of water is $\frac{4}{3}$ . The apparent height of the flame from the eyes of fish is -

$5.5 m$

$6 m$

$\frac{8}{3} m$

$\frac{20}{3} m$

Apparent height of flame above water surface.
$h' = μ h = \frac{4}{3} \times 2 = \frac{8}{3} m$
Therefore, apparent height of the flame from the eye of fish
$= d + h' = 4 + \frac{8}{3} = \frac{20}{3} m$

Q. In a pond of water, a flame is held 2m above the surface of the water. A fish is at depth of 4m from the water surface. Refractive index of water is 34​ . The apparent height of the flame from the eyes of fish is -

5.5m

6m

38​m

320​m