In a mole of water vapour at STP, the volume actually occupied or taken up by the molecules (i.e., Avogadro number × the volume of one molecule) is

Question

In a mole of water vapour at STP, the volume actually occupied or taken up by the molecules (i.e., Avogadro number × the volume of one molecule) is (A) less than 0.1 % of 22.4 litres (B) about 10 % of the volume of the container of 22.4 litres (C) between 10 % to 20 % of 22.4 litres (D) between 2 % to 5 % of 22.4 litres.

Tardigrade Admin · Accepted Answer

One mole of water =18 g =18 cm 3 (density of water =1 g / cm 3 ) Volume of one mole of water vapours =22.4 L =22400 cm 3 Percentage volume actually occupied by the water molecules =(18/22400) × 100=(9/112) < 0.1 %

Q. In a mole of water vapour at $STP$ , the volume actually occupied or taken up by the molecules (i.e., Avogadro number $\times$ the volume of one molecule) is

less than $0.1%$ of $22.4$ litres

about $10%$ of the volume of the container of $22.4$ litres

between $10%$ to $20%$ of $22.4$ litres

between $2%$ to $5%$ of $22.4$ litres.

One mole of water $= 18 g = 18 c m^{3}$

(density of water $= 1 g / c m^{3}$ )

Volume of one mole of water vapours $= 22.4 L = 22400 c m^{3}$

Percentage volume actually occupied by the water molecules

$= \frac{18}{22400} \times 100 = \frac{9}{112} < 0.1%$

Q. In a mole of water vapour at STP, the volume actually occupied or taken up by the molecules (i.e., Avogadro number × the volume of one molecule) is

less than 0.1% of 22.4 litres

about 10% of the volume of the container of 22.4 litres

between 10% to 20% of 22.4 litres

between 2% to 5% of 22.4 litres.