In a metre bridge experiment the balance point is obtained if the gaps are closed by 2 Ω and 3 Ω. A shunt of X Ω is added to 3 Ω resistor to shift the balancing point by 22.5 cm. The value of X is

Question

In a metre bridge experiment the balance point is obtained if the gaps are closed by 2 Ω and 3 Ω. A shunt of X Ω is added to 3 Ω resistor to shift the balancing point by 22.5 cm. The value of X is  (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

(2/((3 x)3+x))=(40+22.5/60-22.5)=(62.5/37.5)=(5/3) (6/5)=(3 x/3+x) 6+2 x=5 x ⇒ x=2

Q. In a metre bridge experiment the balance point is obtained if the gaps are closed by $2 Ω$ and $3 Ω$ . A shunt of $X Ω$ is added to $3 Ω$ resistor to shift the balancing point by $22.5 c m$ . The value of $X$ is _______

$\frac{2}{( \frac{3 x}{3 + x} )} = \frac{40 + 22.5}{60 - 22.5} = \frac{62.5}{37.5} = \frac{5}{3}$
$\frac{6}{5} = \frac{3 x}{3 + x}$
$6 + 2 x = 5 x \Rightarrow x = 2$

Q. In a metre bridge experiment the balance point is obtained if the gaps are closed by 2Ω and 3Ω. A shunt of XΩ is added to 3Ω resistor to shift the balancing point by 22.5cm. The value of X is _______

(3+x3x​)2​=60−22.540+22.5​=37.562.5​=35​ 56​=3+x3x​ 6+2x=5x⇒x=2

Q. In a metre bridge experiment the balance point is obtained if the gaps are closed by $2 Ω$ and $3 Ω$ . A shunt of $X Ω$ is added to $3 Ω$ resistor to shift the balancing point by $22.5 c m$ . The value of $X$ is _______

$\frac{2}{( \frac{3 x}{3 + x} )} = \frac{40 + 22.5}{60 - 22.5} = \frac{62.5}{37.5} = \frac{5}{3}$
$\frac{6}{5} = \frac{3 x}{3 + x}$
$6 + 2 x = 5 x \Rightarrow x = 2$