In a large building, there are 12 bulbs of 40 W, 4 bulbs of 100 W , 7 fans of 60 W and 1 heater of 1 kW. The voltage of the electric mains is 230 V. The minimum capacity of the main fuse of the building will be A.

Question

In a large building, there are 12 bulbs of 40 W, 4 bulbs of 100 W , 7 fans of 60 W and 1 heater of 1 kW. The voltage of the electric mains is 230 V. The minimum capacity of the main fuse of the building will be A. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

P text total =V × I 12 × 40+4 × 100+7 × 60+1 × 1000=V × I 480+400+420+1000=230 I ∴ I=(2300/230) =10 A

Q. In a large building, there are $12$ bulbs of $40 W$ , $4$ bulbs of $100 W, 7$ fans of $60 W$ and $1$ heater of $1 kW$ . The voltage of the electric mains is $230 V$ . The minimum capacity of the main fuse of the building will be _____ $A$ .

$P_{total} = V \times I$
$12 \times 40 + 4 \times 100 + 7 \times 60 + 1 \times 1000 = V \times I$
$480 + 400 + 420 + 1000 = 230 I$
$∴ I = \frac{2300}{230}$
$= 10 A$

Q. In a large building, there are 12 bulbs of 40W, 4 bulbs of 100W,7 fans of 60W and 1 heater of 1kW. The voltage of the electric mains is 230V. The minimum capacity of the main fuse of the building will be _____ A.

Ptotal ​=V×I 12×40+4×100+7×60+1×1000=V×I 480+400+420+1000=230I ∴I=2302300​ =10A

Q. In a large building, there are $12$ bulbs of $40 W$ , $4$ bulbs of $100 W, 7$ fans of $60 W$ and $1$ heater of $1 kW$ . The voltage of the electric mains is $230 V$ . The minimum capacity of the main fuse of the building will be _____ $A$ .

$P_{total} = V \times I$
$12 \times 40 + 4 \times 100 + 7 \times 60 + 1 \times 1000 = V \times I$
$480 + 400 + 420 + 1000 = 230 I$
$∴ I = \frac{2300}{230}$
$= 10 A$