In a hydraulic jack as shown, mass of the car W=800 kg , A1=10 cm 2, A2=10 m 2. The minimum force F required to lift the car is

Question

In a hydraulic jack as shown, mass of the car W=800 kg , A1=10 cm 2, A2=10 m 2. The minimum force F required to lift the car is (A) 1 N (B) 0.8 N (C) 8 N (D) 16 N

Tardigrade Admin · Accepted Answer

Pressure in a liquid is divided equally so we can say pressure at both the pistons should be same

\Rightarrow \frac{F _{1}}{A _{1}} = \frac{F _{2}}{A _{2}}

Substituting values,
Where,

F_{1} = F

A_{1} = 10 c m^{2}

A_{2} = 10 m^{2} = 10 \times 1 0^{4} c m^{2}

F_{2} = 8000 N

\Rightarrow F = 0.8 N

{Take g = 10 m / s^{2}}

Q. In a hydraulic jack as shown, mass of the car W=800kg,A1​=10cm2,A2​=10m2. The minimum force F required to lift the car is

1 N

0.8 N

8 N

16 N

Pressure in a liquid is divided equally so we can say pressure at both the pistons should be same ⇒A1​F1​​=A2​F2​​ Substituting values, Where, F1​=F A1​=10cm2 A2​=10m2=10×104cm2 F2​=8000N ⇒F=0.8N {Takeg=10m/s2}

Q. In a hydraulic jack as shown, mass of the car $W = 800 k g, A_{1} = 10 c m^{2}, A_{2} = 10 m^{2}$ . The minimum force $F$ required to lift the car is