Question

In a frequency distribution, the mid value of a class is 10 and the width of the class is 6. The lower limit of the class is

• A. 6
• B. 7
• C. 8
• D. 12

Answer 1

Answer: (B)

Let $x$ be the upper limit and $y$ be the lower limit.
Since the mid value of the class is 10
$\therefore \frac{x+y}{2}=10\Rightarrow x+y=20$ ....(1)
and $x-y=6$ (width of the class = 6) ...(2)
By solving (1) and (2), we get y = 7.
Hence, lower limit of the class is 7.